14x^2-36x-18=0

Solution for 14x^2-36x-18=0 equation:

14x^2-36x-18=0

a = 14; b = -36; c = -18;
Δ = b2-4ac
Δ = -362-4·14·(-18)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-48}{2*14}=\frac{-12}{28}
=-3/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+48}{2*14}=\frac{84}{28}
=3
$